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c語言一元二次方程求根程序 C語言中如何任意輸入一組數(shù),并判斷正負(fù)數(shù)的個(gè)數(shù)?

C語言中如何任意輸入一組數(shù),并判斷正負(fù)數(shù)的個(gè)數(shù)?#include<stdio.h>#include<stdlib.h>main()//scanf的{ int plus=0,neg

C語言中如何任意輸入一組數(shù),并判斷正負(fù)數(shù)的個(gè)數(shù)?

#include<stdio.h>#include<stdlib.h>main()//scanf的{ int plus=0,negative=0 double s printf("請輸入一組數(shù)(以0結(jié)束輸入):n") while(1) { scanf("%lf",&s) if(s>0) plus else if(s<0) negative else break } printf("共有正數(shù)%d個(gè)n",plus) printf("共有負(fù)數(shù)%d個(gè)n",negative) system("pause")}main()//gets的{ int plus=0,negative=0 char s[100] printf("請輸入一組數(shù)(以0結(jié)束輸入):n") while(1) { gets(s) if(s[0]=="0") break else if(s[0]=="-") negative else plus } printf("共有正數(shù)%d個(gè)n",plus) printf("共有負(fù)數(shù)%d個(gè)n",negative) system("pause")}getchar???這個(gè)只能輸入一個(gè)字符??!比如:23。已經(jīng)是兩個(gè)字符了??!

C語言中任意輸入一組數(shù),并判斷正負(fù)數(shù)的個(gè)數(shù)?

#include<stdio.h>#include <stdlib.h>int main(){ int i int zhengshu=0 for(i=0i<=4i ) { scanf("%d",&i) if(i>0) { zhengshu } } printf("正數(shù)個(gè)數(shù):%d 負(fù)數(shù)個(gè)數(shù):%d",zhengshu,5-zhengshu) return 0}