c語(yǔ)言進(jìn)制轉(zhuǎn)換編程 如何將sql中十六進(jìn)制轉(zhuǎn)換十進(jìn)制?
如何將sql中十六進(jìn)制轉(zhuǎn)換十進(jìn)制?if exists(select * from sysobjects where name="p_zh" and type="p")drop procedure p_
如何將sql中十六進(jìn)制轉(zhuǎn)換十進(jìn)制?
if exists(select * from sysobjects where name="p_zh" and type="p")drop procedure p_zhcreate procedure p_zh@str varchar(10),--十六進(jìn)制數(shù)@ss int output--轉(zhuǎn)換后的十進(jìn)制數(shù)asbegindeclare @len int --十六進(jìn)制數(shù)的長(zhǎng)度declare @st char(1) --取十六進(jìn)制字符串里的字符declare @st1 int--將取出的十六進(jìn)制字符串里的字符轉(zhuǎn)換成十進(jìn)制數(shù)declare @le int --冪的值set @ss=0set @len=len(@str)select @lenset @le=@len 1while(@len>=1)beginset @st=substring(@str,@le-@len,1)select @st--判斷是什么類的數(shù),該怎么轉(zhuǎn)換成十進(jìn)制數(shù)if(@st in("1","2","3","4","5","6","7","8","9","0")) set @st1=convert(int,@st)if(@st in("A","a")) set @st1=10 if(@st in("B","b")) set @st1=11 if(@st in("C","c")) set @st1=12 if(@st in("D","d")) set @st1=13if(@st in("E","e")) set @st1=14 if(@st in("F","f")) set @st1=15set @len=@len-1set @st1=@st1*power(16,@len)set @ss=@ss @st1set @len=@len 1set @len=@len-1endselect @ss "十進(jìn)制"end--例:declare @sls varchar(10)declare @ss intset @sls="a5a8"set @ss=0execute p_zh @sls,@ss output--可能有點(diǎn)煩,但我會(huì)的就是這個(gè)
SQL數(shù)據(jù)庫(kù)中密碼16進(jìn)制怎么轉(zhuǎn)換為字符串?
要看你是什么編碼。如果是ASC碼那么就是8位2進(jìn)制一個(gè)字符,也就是兩個(gè)十六進(jìn)制位。所以,你可以將這個(gè)十六進(jìn)制字符串除0x以外,兩位一組,每一組可以使用CHAR(0x0C)的方式轉(zhuǎn)換為字符,再串加在一起就行了。如果是UNICODE字符,那么就是4位十六進(jìn)制(16位二進(jìn)制)一組進(jìn)行轉(zhuǎn)換。如第一個(gè)字符就是:select nchar(0x0C45),第二個(gè)字符就是select nchar(0x0000)
sql如何將16進(jìn)制數(shù)的列轉(zhuǎn)換成10進(jìn)制數(shù)的列?
利用SQLSERVER中的varbinary來(lái)間接實(shí)現(xiàn)。16進(jìn)制字符串轉(zhuǎn)10進(jìn)制bigint(0-FFFFFFFFFFFFFFFF):由于二進(jìn)制比較容易轉(zhuǎn)換為bigint 所以先將字符串轉(zhuǎn)為二進(jìn)制varbinary,再轉(zhuǎn)換為10進(jìn)制 10進(jìn)制轉(zhuǎn)16進(jìn)制字符串(bigint正負(fù)數(shù)都可以):相同的思路目前可以將二進(jìn)制varbinary轉(zhuǎn)換為字符串比較容易,那么先將10進(jìn)制轉(zhuǎn)二進(jìn)制再進(jìn)行16進(jìn)制字符串輸出以上代碼測(cè)試環(huán)境WIN2003 SQLSERVER2008
Oracle中用SQL語(yǔ)句如何實(shí)現(xiàn)進(jìn)制間互相轉(zhuǎn)換?
首先,字符串必須是數(shù)字形式的字符串,如“12345”或“-12345”等。然后需要用to_number函數(shù)進(jìn)行轉(zhuǎn)換。如:1select to_number("12345") from dual這樣就將字符轉(zhuǎn)成了數(shù)字,并可以參與加減乘除的運(yùn)算。這個(gè)你估計(jì)得自定義函數(shù)了,不能直接用to_number創(chuàng)建函數(shù)12345678910create or replace function isNumber(p in varchar2)return numberistest numberbegintest := to_number(p)return testexceptionwhen VALUE_ERROR then return 0end測(cè)試1,純數(shù)字測(cè)試2 帶非數(shù)字的字符測(cè)試3,負(fù)數(shù)測(cè)試4 小數(shù)測(cè)試5 0總之就是測(cè)試5和測(cè)試2的結(jié)果是一樣,這個(gè)你看你打算怎么解決吧拓展資料有沒(méi)有小數(shù)點(diǎn)?如果有小數(shù)點(diǎn)的話SELECT trunc(to_number("1234,56897"),2) from dual如果全是整的話,那么就是select to_number("1234,56897"),2) from dual